28-[3c+4]=2[c+6]+c

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Solution for 28-[3c+4]=2[c+6]+c equation:


Simplifying
28 + -1[3c + 4] = 2[c + 6] + c

Reorder the terms:
28 + -1[4 + 3c] = 2[c + 6] + c
28 + [4 * -1 + 3c * -1] = 2[c + 6] + c
28 + [-4 + -3c] = 2[c + 6] + c

Combine like terms: 28 + -4 = 24
24 + -3c = 2[c + 6] + c

Reorder the terms:
24 + -3c = 2[6 + c] + c
24 + -3c = [6 * 2 + c * 2] + c
24 + -3c = [12 + 2c] + c

Combine like terms: 2c + c = 3c
24 + -3c = 12 + 3c

Solving
24 + -3c = 12 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.
24 + -3c + -3c = 12 + 3c + -3c

Combine like terms: -3c + -3c = -6c
24 + -6c = 12 + 3c + -3c

Combine like terms: 3c + -3c = 0
24 + -6c = 12 + 0
24 + -6c = 12

Add '-24' to each side of the equation.
24 + -24 + -6c = 12 + -24

Combine like terms: 24 + -24 = 0
0 + -6c = 12 + -24
-6c = 12 + -24

Combine like terms: 12 + -24 = -12
-6c = -12

Divide each side by '-6'.
c = 2

Simplifying
c = 2

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